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5a^2+6a-32=0
a = 5; b = 6; c = -32;
Δ = b2-4ac
Δ = 62-4·5·(-32)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-26}{2*5}=\frac{-32}{10} =-3+1/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+26}{2*5}=\frac{20}{10} =2 $
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